Sunday, 20 January 2019

JKPSC Recruitment 2019 Husbandry Department (200 Vacancies)


https://www.newgovtjobs.in.net/2019/01/jkpsc-recruitment-2019-husbandry.html


JKPSC Recruitment 2019: JKPSC Jammu invites online applications from the permanent residents of Jammu and Kashmir state, for medical recruitment posts of Veterinary Assistant Surgeon in J&K Animal & Sheep Husbandry Departments - J&K Animal Husbandry (Gazzetted) Service and J&K Sheep Husbandry (Gazzetted) Service. The last date for submission of applications is 23rd January 2019.

Notification No: PSC/Exam/87/2018

Name of the Post
No of Vacancies
Veterinary Assistant Surgeon in Animal Husbandry Department
110
Veterinary Assistant Surgeon in Sheep Husbandry Department
90

Age Limit: Minimum 18 years; Maximum 43 years for RBA / SC / ST / SLC, 42 years for PWD, 40 years for In-service, 48 years for Ex-serviceman.

Pay Scale: 52700 - 166700 (Level-9)

Eligibility:

(1) Bachelor’s Degree in Veterinary Sciences & Animal Husbandry from a recognized University or institute.
(2) Candidates is permanent resident of J&K State.

Examination Fee: 400/- for General, 200/- for Reserved category, No fee for PHC candidates.

Selection Process: Written Examination (Objective Type). The exam shall be held on 17th February 2019.

How to Apply: Eligible candidates apply online through JKPSC Website portal from 1st January 2019. The last date for filing of online Application complete in all respects along with the requisite fee (online mode only) is 23/01/2019.

For More Official Details: Click Here
For Apply Online: Click Here


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